Derivation | Formula | Sum of first n squares or square numbers 1^2 + 2^2 + 3^2 + 4^2 +...n^2

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Derivation of formula for sum of first n natural numbers, its squares & cubes.#sumofnnaturalnumbersПодробнее

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Prove by the principle of induction for all n belongs to N | 1^2 + 2^2 +...+ n^2 = n(n+1)(2n+1)/6Подробнее

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1³/1 + 1³+2³/1+3 + 1³+2³+3³/1+3+5 + ..... + upto n terms = n/24(2n² + 9n + 13) @EAGПодробнее

1³/1 + 1³+2³/1+3 + 1³+2³+3³/1+3+5 + ..... + upto n terms = n/24(2n² + 9n + 13) @EAG

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Prove the following by the principle of induction | 1^2 + 3^2 + 5^2 +…..+ (2n-1)^2 = n(2n-1)(2n+1)/3Подробнее

Prove the following by the principle of induction | 1^2 + 3^2 + 5^2 +…..+ (2n-1)^2 = n(2n-1)(2n+1)/3

Prove by the principle of Mathematical induction | 1^3 + 2^3 + 3^3 + …. + n^3 == [(n(n+1))/2]^2Подробнее

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The sum of the first n terms of the series 1^2+ 2.2^2+3^2 +2.4^2+.... is (n(n+1)^2)/2when n is ...Подробнее

The sum of the first n terms of the series 1^2+ 2.2^2+3^2 +2.4^2+.... is (n(n+1)^2)/2when n is ...

Mathematical Induction @EAGПодробнее

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1.3+2.4+3.5+...+n(n+2)=n(n+1)(2n+7)/6 #MathematicalInduction #Algebra L429Подробнее

1.3+2.4+3.5+...+n(n+2)=n(n+1)(2n+7)/6 #MathematicalInduction #Algebra L429

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Prove by Induction sum of first n Cubes ,1^3+2^3+3^3+... +n^3=n^2(n+1)^2÷4Подробнее

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Principle Of Mathematical Induction | Sum Of First n Natural Numbers Using Mathematical InductionПодробнее

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prove by the principle of Mathematical induction that 1²+2²+3²+...+n²=(n(n+1)(2n+1))/6Подробнее

prove by the principle of Mathematical induction that 1²+2²+3²+...+n²=(n(n+1)(2n+1))/6

Inter Maths-1(A)- Mathematical Induction- exercise-2(a) - 14,15 problemsПодробнее

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